Gravity simulator

Suppose a moon is in a circular orbit around a planet and that the planet is on a circular orbit around a star. M = Mass of star m = mass of planet R = Distance of planet from star r = Distance of moon from planet T = Period of planet's orbit t = Period of moon's orbit H = Hill radius h = Hill constant The moon's orbit is stable if t < h T where h represents a dimensionless number of order unity. Equivalently, the maximum stable radius for a moon r is given by r < h R (m/M)^(1/3) < h H The "Hill radius" is defined as H = R (m/M)^(1/3) The Hill radius is also the distance to the L1 and L2 Lagrange points. The Earth's moon orbits at 1/5 this distance. Also, asteroids this close to the Earth are likely to either: A planet's "zone of gravitational dominance" can be defined as the maximum stable radius of a moon. An object is defined as a planet if it is large enough to be round and if it is not within the gravitational zone of a larger object.


Hill radius
Hill radius of the planets
With the gravity simulator at phet.colorado.edu "My Solar System", you can set up arbitrary planet-moon orbits and test if they are stable. The force equation that the simulator uses is Force = G * Mass * Mass / r^2 G = 10^4 Circular orbit: G * Mass / r^2 = Velocity^2 / r A planet with a circular orbit and a moon can be set up with Mass Position Velocity X Y X Y Body 1 100. 0 0 0 0 Sun Body 2 1. 100 0 0 100 Planet Body 3 .01 110 0 0 120 Moon Moons are stable if r < h H Using the simulator, we can characterize the value of the Hill constant as a function of m/M, both for a prograde and a retrograde moon. What results do you get?
Is there room in the solar system for more planets?
If a planet is added between Jupiter and Saturn, we can test its stability using the gravity simulator. G = Gravitational Constant = 10^4 M = Mass of Sun R = Planet Radius V = Velocity in the Y direction = (G M / R)^.5 For a circular orbit We can simulate a planet between Jupiter and Saturn by setting Mass Position Velocity X Y X Y Body 1 100. 0 0 0 0 Sun Body 2 .096 100 0 0 100 Jupiter Body 3 .0288 140 0 0 84.5 Saturn clone Body 4 .0288 183 0 0 73.9 Saturn The planet masses and radii have been set in proportion to the actual values for the solar system. For instance, Mass of Jupiter / Mass of Sun = 318 Earth masses / 330000 Earth masses = .096 / 100 Saturn orbit / Jupiter orbit = 9.54 AU / 5.20 AU = 138 / 100 A planet can be added between the Venus and the Earth with Mass Position Velocity X Y X Y Body 1 100. 0 0 0 0 Sun Body 3 .000219 100 0 0 100 Venus Body 4 .000303 120 0 0 91.3 Tatooine Body 2 .000303 138 0 0 85.1 Earth Are these systems stable? What is the minimum mass of the middle planet? How close together can two Earth-sized planets be in the Kuiper belt?
Roche radius
If you were standing on Saturn's moon Mimas, Saturn's tidal gravity would lift you into space. This is why Mimas doesn't capture ring material even though it orbits within Saturn's rings. M = Mass of planet m = Mass of moon R = Planet-moon distance r = radius of moon The gravitational acceleration from the planet at the center of the moon is G M R^-2 The gravitational acceleration from the planet at the point on the moon closest to the planet is G M (R-r)^-2 ~ G M R^-2 (1+2r/R) ~ G M R^-2 + 2 G M r / R^3 ~ Gravity at center + a differential term The difference between the gravitational acceleration at the surface and at the center is 2 G M r / R^3 Equate this with the acceleration at the surface from the moon's gravity. 2 G M r / R^3 = G m / r^2 R ~ r (2M/m)^(1/3) This is the "Roche radius", the closest a moon can get to a planet without being pulled apart. This is analogous to the "gravitational dominance" calculation above. Replacing masses with densities, R ~ Radius_of_Planet * (2 * Density_of_planet / Density_of_moon)^(1/3) If a planet and moon have identical densities, then a moon near the planet's surface is always pulled apart. Saturn has the smallest density and so is the least favorable for rings. Rings around other planets can be proportionally larger.
Earth Roche radius
The moon was formed when a planet-sized object struck the Earth. The debris from the collision that was within the Earth's Roche radius formed a ring that rivaled Saturn's and then fell back to the Earth. The debris beyond the Roche radius coalesced into the moon. The Roche radius is the boundary for tidal disruption of a moon. If a moon is inside the Roche radius it gets tidally disrupted and becomes a ring. If a moon is outside the Roche radius it is safe. Roche radius = 2.44 * Planet radius * (Planet density / Moon density)^1/3 For an object with the moon's density, what is Roche radius / Earth radius Roche radius / Moon's present radius For an orbiting moon, Angular momentum = (Moon mass) * (Moon velocity) * (Moon orbit radius) For a spinning sphere, Angular momentum = 2/5 * Mass * Radius^2 * (Spin angular velocity) The Earth-moon tidal interaction caused the moon's orbit to spiral out to its present location and for the Earth's spin to slow down. If you assume that the moon was formed at the Roche radius, that the moon is always tidally locked as it spirals outward, and that angular momentum is conserved by the tidal interaction, what was the Earth's initial spin period?
Solar system data
Semi-major Mass Escape Orbit Hill axis (AU) (Earth speed speed number masses) (km/s) (km/s) Sun 0. 333000 618. 0. Mercury .387 .0553 4.3 47.9 .0038 Venus .723 .8150 10.46 35.0 .0093 Earth 1.000 1.0000 11.2 29.8 .0100 Moon .0123 1.02 .160 Mars 1.524 .1074 5.03 24.1 .0048 Vesta 2.36 .0000447 19.3 .0004 Ceres 2.766 .00016 .51 17.9 .0005 Pallas 2.77 .0000359 17.6 .0003 Jupiter 5.203 317.83 59.5 13.1 .0683 Saturn 9.537 95.16 35.5 9.64 .0457 Uranus 19.19 14.50 21.3 6.81 .0244 Neptune 30.07 17.20 23.5 5.43 .0258 Pluto 39.48 .00220 1.23 4.74 .0013 Charon .000271 .345 Haumea 43.34 .00070 Makemake 45.79 .0007 Eris 67.67 .00278 3.44 1 AU = 1.50*10^11 m 1 year = 365.25 days = 31557600 s 1 Earth mass = 5.974*10^24 kg Jupiter Hill radius = .19 AU The Hill radius is the distance to the L1 and L2 Lagrange points. Moons outside ~ 1/3 of the Hill radius of a planet are unstable. Planets within ~ 6 Hill radii of each other are unstable. Hill number = (1 - eccentricity) * cube_root{mass_planet/(3*mass_sun)} Hill radius = semi_major_axis * (1 - eccentricity) * cube_root{mass_planet/(3*mass_sun)} Moons within a planet's Roche radius are vulnerable to tidal disruption. Roche radius = 2.44 * Planet radius * (Planet density / Moon density)^1/3
http://en.wikipedia.org/wiki/Hill_sphere http://en.wikipedia.org/wiki/Lagrangian_point
Virial theorem for gravity
Circular orbits, turbulent motions of gas clouds, and the heating of the sun are all examples of the Virial theorem. For an object on a circular orbit, what is the ratio X = Kinetic energy / Gravitational potential energy When two spiral galaxies collide, the merger product tends to be an elliptical galaxy. https://www.youtube.com/watch?v=Cd9cBlvfjow In an elliptical galaxy, stars have random orbits, and if you calculate X = Sum of the kinetic energy of the stars / Sum of gravitational potential energy of stars you get the same value X that you got for a circular orbit. The Virial theorem also covers the motions of the nuclei in the sun. X = Kinetic energy of all particles in the sun / Gravitational potential energy of the sun The gravitational potential energy of a uniform-density sphere is Energy = 3/5 G Mass^2 / Radius and the characteristic thermal speed of an atom is Kinetic energy = 1/2 Mass Thermal_Speed^2 Using the Virial theorem, what is the characteristic thermal speed of protons in the sun? Temperature is related to thermal speed by Kinetic energy = 3/2 Boltzmann_Constant * Temperature For the sun, what temperature does this correspond to?
Orion nebula
Mass ~ 2000 Solar masses Radius ~ 12 light years 700 stars 150 protoplanetary nebulae What is the escape velocity of the Orion Nebula and what is the gravitational potential energy? A supernova of 10 solar masses ejects ~ half of its mass into the nebula at a velocity of ~ 10,000 km/s. How much kinetic energy is this? How many supernovae does it take to disperse the gas in the cloud?
Hohmann trajectory
Orbit Orbit radius speed AU km/s Earth 1.000 29.8 Mars 1.524 24.1 The most efficient way to get from the Earth to Mars is with a Hohmann trajectory. v = Earth orbital velocity r = Earth orbital radius h = Hohmann velocity at Earth V = Mars orbital velocity R = Mars orbital radius H = Hohmann velocity at Mars In a Hohmann trajectory, the rocket starts with the same trajectory as the Earth and increases its velocity from v to (v+h). The rocket now has an orbit where the perigee is at the Earth's orbit and the apogee is at Mars' orbit. Upon arriving at Mars it will be moving too slow to match trajectories with Mars and so it has to increase its speed by H. Velocity at Earth's orbit before firing rockets v Velocity at Earth's orbit after firing rockets v + h Velocity at Mars' orbit before firing rockets V - H Velocity at Mars' orbit after firing rockets V Energy of a rocket in the Sun's gravitational field = G * Mass_of_Sun * Mass_of_Rocket / Distance_from_Sun Using conservation of energy and angular momentum, what are h and H? http://en.wikipedia.org/wiki/Hohmann_transfer_orbit
Questions
Hubble image of Saturn
Rings of Saturn
A = Outer radius of the A ring of Saturn / Radius of Saturn R = Roche radius of Saturn for ice / Radius of Saturn Using the image of Saturn, what would you estimate is the value of A? Using the Roche theory, what is the value of R?